x^2-20x-8000=0

Solution for x^2-20x-8000=0 equation:

x^2-20x-8000=0

a = 1; b = -20; c = -8000;
Δ = b2-4ac
Δ = -202-4·1·(-8000)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-180}{2*1}=\frac{-160}{2}
=-80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+180}{2*1}=\frac{200}{2}
=100
$